Tuesday, 27 October 2009

Sampras beats Agassi in Macau showdown 森柏斯挫宿敵阿加斯 (森柏斯挫宿敌阿加斯)


Pic Source : AP Photos
Andre Agassi shares a light moment with Pete Sampras during a friendly exhibition

Former world number one Pete Sampras beat long-time rival Andre Agassi at the Venetian Macao Tennis Showdown 2009. This is the first time the two had played since Sampras won in the 2002 U.S. Open final for his then-record 14th Grand Slam. Sampras led their head-to-head 20 to 14.

The match was first preceded by a 45 mins timed encounter between junior no.1 Yuki Bhambri and America's leading junior Ryan Harrison.

Playing in front of 11,000 enthusiastic fans strong crowd at the CotaiArena, Sampras lost the first set 3-6, but rallied to take the second 6-3 and then finished off Agassi in 10-8 tie-breaker. The pair played against each other 34 times in their professional careers.

The two former No. 1s have 124 career titles and 22 Grand Slams - Agassi has eight and Sampras 14. Agassi is one of only 6 men to have won all four majors and also won Olympic gold in Atlanta in 1996. Sampras' 14 Slams was a record until Federer won Wimbledon this year.

Match Results
Yuki Bhambri (IND) def. Ryan Harrison (USA) 5-5 15-0
Pete Sampras (USA) def. Andre Agassi (USA) 3-6 6-3 10-8
P. Sampras (USA) & Y. Bhambri (IND) def. A. Agassi (USA) & R. Harrison (USA) 7-5

澳門威尼斯人渡假村酒店主辦的“網球爭霸戰”, 10月25日在金光綜藝館上演三場精彩全場爆滿表演賽。 威尼斯人網球爭霸戰二○○九連續第三年為球迷帶來精彩比賽。 今次安排全新的對壘組合。 當中90年代叱吒風雲的兩位網球手 - 球王森柏斯與美國網壇名宿阿加斯七年後再續前緣成為重頭戲。 兩位球手是2002年美國公開賽決賽後首度對決。

森柏斯先輸一盤3:6, 繼後以同樣比數追平。 兩位宿敵各勝一盤後, 決勝的第3盤採用「超級決勝局」制, 森柏斯決勝分開出Ace險勝10:8。

森柏斯在職業生涯贏得十四項大滿貫錦標, 阿加斯是史上唯一一位“金滿貫”得主。